Math, asked by mehak8406, 6 months ago

(vi) 3x2 - x-4 with the sum of roots and product of roots

Answers

Answered by gk9995286
0

Answer:

x2 - 5x + 6 = 0

and

ax2 + bx + c = 0

we get

a = 1, b = -5 and c = 6

Therefore,

Sum of the roots = -b/a = -(-5)/1 = 5

Product of the roots = c/a = 6/1 = 6

Example 2 :

Find the sum and product of roots of the quadratic equation given below.

x2 - 6 = 0

Solution :

Comparing

x2 - 6 = 0

and

ax2 + bx + c = 0

we get

a = 1, b = 0 and c = -6

Therefore,

Sum of the roots = -b/a = 0/1 = 0

Product of the roots = c/a = -6/1 = -6

Example 3 :

Find the sum and product of roots of the quadratic equation given below.

3x2 + x + 1 = 0

Solution :

Comparing

3x2 + x + 1 = 0

and

ax2 + bx + c = 0

we get

a = 3, b = 1 and c = 1

Therefore,

Sum of the roots = -b/a = -1/3

Product of the roots = c/a = 1/3

Example 4 :

Find the sum and product of roots of the quadratic equation given below.

3x2 + 7x = 2x - 5

Solution :

First write the given quadratic equation in standard form.

3x2 +7x = 2x - 5

3x2 + 5x + 5 = 0

Comparing

3x2 + 5x + 5 = 0

and

ax2 + bx + c = 0

we get

a = 3, b = 5 and c = 5

Therefore,

Sum of the roots = -b/a = -5/3

Product of the roots = c/a

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