Question

(vi) 4x² = 1 without finding roots comment the nature of the root
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Answer 1

Consider the equation 4x2−4x+1=0

Consider the equation 4x2−4x+1=0This is in the form of ax2+bx+c=0. The co-efficient are a=4,b=−4,c=1

Consider the equation 4x2−4x+1=0This is in the form of ax2+bx+c=0. The co-efficient are a=4,b=−4,c=1△=b2−4ac,△(−4)2−4(4)(1),△=16−16

Consider the equation 4x2−4x+1=0This is in the form of ax2+bx+c=0. The co-efficient are a=4,b=−4,c=1△=b2−4ac,△(−4)2−4(4)(1),△=16−16∴△=0. Therefore, roots are real and equal

Answer 2

Answer:

-1.7

Step-by-step explanation:

4x2=1

X2=1-4

x=root 3

x= -1.7