(vi) 6х + Зу = 6xy
2x +4y =5xy
+
3х – у
=
(viii) 3х + у
1
1
-1
=
2(3х + y) 2(3х - у)
8
Answers
Answered by
0
Answer:
don't know
Step-by-step explanation:
Mark me as brainlist
Similar questions