Math, asked by wwwthakurmanoj1977, 3 days ago

(vi) 6х + Зу = 6xy
2x +4y =5xy


+
3х – у
=
(viii) 3х + у
1
1
-1
=
2(3х + y) 2(3х - у)
8​

Answers

Answered by ppritikumari489
0

Answer:

don't know

Step-by-step explanation:

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