Question

(vi) a = 3, d = 2; a10, an​

Answer 1

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Given:-

• a=3
• d=2

To Find:-

• $a_10\:and\:a_n$

Solution:-

We know that

$a_10=a+9d$

$\implies$$a_10 =3+9\left(2\right)$

$\implies$$a_10 = 3+18$

$\implies$$a_10 =21$

Now

We also know that

$a_n =a+\left(n-1\right)d$

$\implies$$a_n =3+\left(n-1\right)2$

$\implies$$a_n =3+2n-2$

$\implies$$a_n =1+2n$

Answers:-

• $a_10 =21$
• $a_n =1+2n$