Question

vi) A parallel plate air condenser has an area 2 x 10* mand separation be
tween the two plate is 1mm. Find its capacity (€, = 8.8 x 10-12 c/NM)​

Answer 1

Answer:

pair of equilateral triangle are similar

Answer 2

Given:

• The area of a parallel plate air condenser as $2$×$10^8m$.
• The separation between the two plate is $1mm$.

To find:

• The capacity of the parallel plate air condenser.

Step-by-step explanation:

• The capacity of the parallel plate is condenser is its ability to contain or receive.
• Let the area of the parallel plate air condenser is $A$.
• We know that the area of the parallel plate air condenser has $2$×$10^8m^2$.
• So,

       $A=2$×$10^8m^2$

• Let the distance between the two plat be $d$
• We know that the distance between the two plate is $1mm$.
• So,

        $d=1mm$

• Convert Millimetre into metres.
• So,

        $d=1$×$10^-3m$

• Let the capacity be $c$.
• The formula to find the capacity is,

        $c=$ε$\frac{A}{d}$

• The value of ε is,

        ε$=8.8$×$10^-12c/NM$

• Now substitute all the values in the equation.

        $c=(8.8$×$10^-12)$$\frac{(2)(10^8)}{(1)(10^-3)}$

• By solving the above equation we get the capacity as,

        $c=1.76$μ$F$

Final answer:

• Therefore the capacity is $c=1.76$μ$F$.