Question

(vi) At constant Temperature, the pressure of 10 dm volume of an ideal gas was increased
from 100 kPa to 200 kPa, new volume will be
a) 20 dm3
b) 10 dm3
c) 5 dm
d) 0.2 dm3
​

Answer 1

Answer:

c) 5 dm3

Explanation:

here v = 10 dm volume

P1 = 100& P2 = 200

p is inversely proportional v (remember p is pressure and v is volume.)

so, P1 v1= P2 V2

V2= P1 v1/P2

= 100×10/200

v2 = 5 dm3

new volume will be 5 dm3.