Question

(vi)
Calculate the acceleration due to gravity at a height of 300km
from the surface of the earth. (M = 5.98 x 10^24 Kg ,R 6400km.​

Answer 1

Answer: g = 8.9 × 10^6

Explanation:

Acceleration due to gravity (g) at height 'h' = GM/ (R+h)²

={6.67 × 10^-11 × 5.98 × 10^24}/ (6400 +300)²

= {39.8866 × 10^(-11+24)}/ 6700²

={39.8866 × 10¹³}/44890000

=3.98866 × 10¹⁴ / 4.489 × 10^7

=0.89× 10^(14-7)

=0.89× 10^7

=8.9 × 10^6

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