(vi)
cot A - tan A = 2 cot 2A
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Answered by
1
Hey Mate!!
CotA-tanA = 2.cot 2A
L.H.S.
=cosA/sinA-sina/cosA
=(cos^2A-sin^2A)/sinA.cosA
=(cos2A)/(1/2.sin2A)
=2.(cos2A/sin2A)
= RHS =2.cot2A
Hence proved.
Hope this helps you!!
Answered by
1
cos A/sinA-sine/cosA
(cos^3A-sin^2A)/sinA-cosA
(cos 2A)/(1/2.sin2A)
2.(cos 3A/sin2A)
R.H.S =2.cot 2A
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