Question

(vi) Determine the electric potential at the midpoint of the line joining two charges 2 × 10^5C
and -1 × 10^5 C placed in vacuum 10 cm apart​

Answer 1

Answer:

-1 × 10^10

Explanation:

2×10^5C + -1 ×10^5 / 2

= -2 × 10^10 / 2

= -1 × 10^10

Answer 2

Answer:

zero is answer

option a in photo is zero