Question

(vi) Five years hence, the age of Jacob will be three times that of his son. Five years
ago, Jacob's age was seven times that of his son. What are their present ages?​

Answer 1

Step-by-step explanation:

Let the present age of Jacob and Son be X and y years respectively.

After 5 years age of Jacob = ( x + 5 ) years

After 5 years age of son = ( y + 5 ) years.

A/Q,

X + 5 = 3 ( Y + 5 )

X + 5 = 3Y + 15

X = ( 3Y + 15 - 5 )

X = 3Y + 10

X - 3Y = 10 ------(1)

Before 5 years age of Jacob = ( X - 5 ) years

Before 5 years age of son = ( Y - 5 ) years

A/Q,

X - 5 = 7 ( Y - 5 )

X - 5 = 7Y - 35

X = 7Y - 35 + 5

X - 7Y = -30 --------(2)

From equation (1) , we get

X - 3Y = 10

X = ( 10 + 3Y ) -----(3)

Putting the Value of X in equation (2),

X - 7Y = -30

10 + 3Y - 7Y = -30

-4Y = -30-10

-4Y = -40

Y = 10

Putting the value of Y in equation (3) ,

X = 10 + 3Y

X = 10 + 3*10

X = 40.

Hemce ,

Age of father is 40 and age of son is 10 year's respectively..

Answer 2

Answer:

Please refer the attachment dear