Math, asked by Anonymous, 7 months ago


(vi) Five years hence, the
age of Jacob will be three times that of his son. Five years
ago, Jacob's age was seven times that of his son. What are their present ages?

My Answer is 25 & 5
Am i Right
If no , then Answer it ​

Answers

Answered by Anonymous
7

Answer:

Let the age of Jacob be x and and age of his son be y

According to first condition

x + 5 = 3(y + 5)

x + 5 = 3y + 15

x - 3y = 15 - 5

x - 3y = 10 ---> 1

According to second condition

x - 5 = 7(y - 5)

x - 5 = 7y - 35

x - 7y = -35 + 5

x - 7y = -30---> 2

Solving 1 & 2

x - 7y = -30

x - 3y = 10

- + -

------------

-4 y = -40

y = 40/4

y = 10

Substitute value of y = 10 in equation 1

x - 3y = 10

x - 3(10) = 10

x = 10 + 30

x = 40

So the present age of Jacob is 40 years and his son age is 10 years..

Answered by brijeshsingh9061
2

Jacob present age is 40 and his son age is 10

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