Math, asked by deepakrane36588, 5 months ago

(vi) Five years hence, the age of Jacob will be three times that of his son. Five years
ago, Jacob's age was seven times that of his son. What are their present

ANSWER

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years

Answers

Answered by satyasaisravan8
0

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