Question

vi.
Five years hence, the age of Jacob will
be three times that of his son. Five
years ago, Jacob's age was seven
times that of his son. What are their
present ages?
​

Answer 1

Answer:

ANSWER

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years.