Question

(vi) mn + m+n+1
(ix) x (y+z) - 5 (y+z)​

Answer 1

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Step-by-step explanation:

$mn + m + n + 1 \\ = (mn + m) + (n + 1) \\ = m(n + 1) + 1(n + 1) \\ = (n+ 1)( m+ 1)$

$x(y + z) - 5(y + z) \\ = (y + z)(x - 5)$

$\huge \color{silver} {\underbrace {\boxed {\colorbox{black}{thnq}}}}$