Question

VI. Numerical Problems, 1. What is the heat in joules required to raise the temperature of 25 grams of water from 0°C to 100°C? What is the heat in Calories? (Specific heat of water = 4.18 J/g °C) ​

Answer 1

Answer:

10450 J or 2500 calories of heat energy are required to raise the temperature of 25 grams of water from 0° C to 100°C.

M=25g C=4.18 J/g Tf=100 Ti=0

Q=25g x4.18j/g (100-0)

Q=25x4.18x(100)

Q=104.5(100)

Q=10,450

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