Question

(vi) sin 3x + sin 2x - sin x = 4 sin x cosx/2cos3x/2​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

We will start with LHS First Answer:-

Sin 3 x + Sin 2x - Sin x = (Sin 3x - Sin x) + Sin 2 x ,;

Sin A- Sin B = 2 Sin (A-B)/2 Cos (A+B)/2 = 2 Sin x Cos 2x + 2 Sin x Cos x ;

Sin 2 A = 2 Sin A Cos A = 2 Sin x [ Cos 2x + Cos x ] ;;

Cos A + Cos B = 2 Cos (A+B)/2 Cos (A-B)/2

= 2 Sin x * 2 Cos 3x/2 Cos x/2

= 4 Sin x * Cos x/2 * Cos 3x/2 = RHS

Step-by-step explanation:

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