Question

vi) The lengths of the sides of a triangular park are 90 m, 70 m, and 40 m, find its area
(a)1340 sqm
(b) 1344 sq m
(c) 1440 sq m (d) 1444 sqm​

Answer 1

Answer:

(b) 1344 sq m

Step-by-step explanation:

Solution -  

Area of a triangle whose three sides are given is given by Heron's formula.

A = sqrt (s (s - a) ( s - b) (s - c))  

Where s is the half perimeter.

s = (a + b + c) / 2  

Given: a = 40m, b = 90m, c = 70m

s = (40 + 90 + 70) / 2

  = 200/2

 

  = 100 m

Area of the triangle A = sqrt (s (s - a) ( s - b) (s - c))

             

                                     = sqrt (100 * (100 - 40) * (100 - 90) * ( 100 - 70))

 

                                     = sqrt ( 100 * 60 * 10 * 30)

 

                                     = 10 sqrt (18000)

   

                                      = 10 sqrt (3600 * 5)

   

                                      = 10 * 60 * sqrt 5

       

                                      = 10 * 60 * 2.24

                           

                                      = 1344 sq. m

Area of the triangular garden = 1344 sq. m

Hope its helpful..

Mark me Brainliest!!