(vi) The temperature on Wednesday was 38.5°C and is increased by 1.7°C on Thursday. Find
the temperature on Thursday.
Answers
Answered by
4
Step-by-step explanation:
Answer:
→ 31°C .
Step-by-step explanation:
\because∵ The average temperature for Monday.Tuesday and Wednesday was 36°C.
→[ M + T + W ]/3 = 36° .
→ M + T + W = 36 × 3 .
\therefore∴ M + T + W = 108° . ....... (1) .
And,
\because∵ The average temperature for Tuesday, Wednesday and Thursday was 38°C .
→ [ T + W + TH ]/3 = 38°C .
→ T + W + TH = 38 × 3 .
\therefore∴ T + W + TH = 114° . ........ (2) .
On subtracting equation (2) and (1), we get
→ TH - M = 6° .
{ And, it's given Temp. on TH is 37°C . }
→ 37 - M = 6.
→ M = 37 - 6 .
\therefore∴ Temperature on Monday was 31°C .
Hence, it is solved.
Answered by
4
38.5+1.7degrees c is 40.2 so 40.2 degrees is anser
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