Question

vi) Two capillaries having radius 0.5mm and 1mm dipped is same liquid.If rise in liquid level in first tube is 3cm then find the rise in liquid level in another tube.​

Answer 1

The rise in liquid level in another tube is 1.5 cm

Explanation:

Given:

Two capillaries having radius 0.5 mm and 1 mm dipped in same liquid

The rise in liquid level in first tube is 3 cm

To find out:

The rise in liquid level in another tube

Solution:

$r_1=0.5$ mm

$r_2=1$ mm

$h_1=3$ cm

$h_2=?$

We know that if T is surface tension, d is the density of the liquid, r is the diameter then the rise in the capillary

$h=\frac{2T\cos\theta}{rdg}$

Thus,

$h\propto\frac{1}{r}$

$\implies \frac{h_1}{h_2}=\frac{r_2}{r_1}$

$\implies h_2=\frac{h_1r_1}{r_2}$

$\implies h_2=\frac{3\times 0.5}{1}$

$\implies h_2=1.5$ cm

Hope this answer is helpful.

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