Question

(vi) Two capillary tubes of radii 0.3 cm and 0.6cm are dipped in the same liquid . the ratio of heights through which the liquid will rise in the tube is

Answer 1

The ratio of heights through which the liquid will rise in the tube is 2:1

Explanation:

Given:

Two capillaries having radius 0.3 mm and 0.6 mm dipped in same liquid

To find out:

The ratio of heights through which the liquid will rise in the tube

Solution:

$r_1=0.5$ mm

$r_2=1$ mm

We know that if T is surface tension, d is the density of the liquid, r is the diameter then the rise in the capillary

$h=\frac{2T\cos\theta}{rdg}$

Thus,

$h\propto\frac{1}{r}$

$\implies \frac{h_1}{h_2}=\frac{r_2}{r_1}$

$\implies\frac{h_1}{h_2}=\frac{0.6}{0.3}$

$\implies \frac{h_1}{h_2}=\frac{2}{1}$

$\implies h_1:h_2=2:1$

Hope this answer is helpful.

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Answer 2

Answer:

your answer is in the above imgs.