Question

(vi) (x - y)?, (x² + y²), (x + y)2 ..., to n terms​

Answer 1

Step-by-step explanation:

We have to find the sum of (x−y)

2

,(x

2

+y

2

),(x+y)

2

,... to n terms

From the progression we know that first term is a=(x−y)

2

Now, let's calculate the common difference d

d=a

2

−a

1

=(x

2

+y

2

)−(x−y)

2

=(x

2

+y

2

)−(x

2

+y

2

−2xy)

=x

2

+y

2

−x

2

−y

2

+2xy

=2xy

We know that the sum of an A.P is given by S

n

=

2

n

×{2a+(n−1)d}

So,

S

n

=

2

n

×{2(x−y)

2

+(n−1)×2xy}

=

2

n

×2{(x−y)

2

+(n−1)xy}

=n{(x−y)

2

+(n−1)xy}

Answer 2

Answer:

hay

Step-by-step explanation:

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