(vi) x2-3x + 1 = (x - 2)2
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=>x²-3x+1=(x-2)²
How to solve :
step 1:First step is to opening the brackets and expanding the terms both sides .
Step2:Making Variable term together and constant term together.
Step3:Then ,let the variable alone and shifts all the constant to the constant side
Identity used here :
(a-b)²=a²+b²-2ab
here ,(x-2)² is in the form of (a-b)² so,apply identity here,
=>x²-3x+1= x²+(2)²-2(x)(2)
=>x²-3x+1=x²+4-4x
Here,we see that x² lies on both sides so,it gets automatically cancelled.
=>-3x+1=4-4x
Now, arranging the terms making like terms together:
=> -3x+4x=4-1
=>x= 3
We get x=3
Check:
Taking LHS
=>x²-3x+1
=>(3)²-3(2)+1
=>9-9+1
=>0+1=1
Taking RHS
=>(x-2)²
=>(3-2)²
=>(1)²=1
Hence,LHS = RHS (Verified)
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