Question

vibrating system of natural frequency 599hz is forced to vibrate with a period force per unit mass of amplitude 100*10 to the power minus 3 calculate the maximum amplitude of vibration of the system​

Answer 1

Answer: ω  

2

=  

0.150 kg

6.30 N/m

​

±  

(0.150 kg)(0.440 m)

17.0 N

​

 

This yields ω=8.23 rad/s or ω=4.03 rad/s. Then :

f=  

2π

ω

​

 gives either f=  

1.31 Hz

​

 or f=  

0.641 Hz

​

Explanation: