Math, asked by faroukaburakabeh, 2 months ago

Victor wants to sell 3 watches, each at the same
price. After negotiating with customers,
however, he ends up selling one at a 30%
discount, one at a 20% discount, and one at a
10% discount. If Victor sold the watches for a
total of $240, how many much money did he
lose by giving the discounts?
A) $45
B) $60
C) $75
D) $90​

Answers

Answered by RvChaudharY50
4

Solution :-

Let us assume that, Marked price of each watch is $x .

so,

→ SP of first watch after 30% discount = (x * 70/100 = $0.7x

→ SP of second watch after 20% discount = (x * 80/100 = $0.8x .

→ SP of third watch after 10% discount = (x * 90/100 = $0.9x

A/q,

→ 0.7x + 0.8x + 0.9x = 240

→ 2.4x = 240

→ x = $ 100

then,

→ Total MP of all three watches = 100 * 3 = $300 .

therefore,

→ Total loss by giving discounts = 300 - 240 = $60 (B) (Ans.B)

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Answered by amitnrw
1

Given : Victor wants to sell 3 watches, each at the same price. After negotiating with customers, however, he ends up selling one at a 30%

discount, one at a 20% discount, and one at a 10% discount.   Victor sold the watches for a total of $240,

To Find : how many much money did he lose by giving the discounts?

A) $45

B) $60

C) $75

D) $90​

Solution:

Let say price of 1 watch = 100 P

Discount  = 30P , 20 P and 10 P

Selling Price =  3 * 100 P  - ( 30P + 20P + 10P )

= 300 P - 60P

= 240P

240P  = 240

=> P = 1

Discount = 60P  = 60 (1) = 60

Money lost in discount = $ 60

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