Question

Vidhya went to a bank to withdraw Rs 1 , 800 . She asked the cashier to give her Rs 50 and Rs 100 notes only. Vidhya got 24 notes in all. Find the number of Rs 50 notes and the number of Rs 100 notes that she received.​

Answer 1

Answer:

let ₹50 coin be x

₹ 100notes be (24-x)

total amount of money in ₹50 coins = 50×x = 50x

total amount of money in₹100 notes = 100(24-x)

=> 2400-100x

A/q

50x + (2400-100x) = ₹1800

50x + 2400 - 100x = ₹1800

50x - 100x = 1800 - 2400

-50x = -600

50x = 600

x = 600/50

x = 12

therefore ₹50 coins = 12

₹100 notes = 24-12

=> 12

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Answer 2

$\huge \sf Answer :$

Rs 50 notes = 10 and Rs 100 notes = 15

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$\huge \sf Solution :$

Let total Rs 50 notes = x

and total Rs 100 notes = y

∴ Total notes = x + y

But we are given total notes = 24

$\sf \implies x+y = 24 \: \: - ①$

Now, Vidhya has total money =50x + 100y

But we are given total money =Rs 1800

$\sf \implies 50x+100y = 1800$

$\sf \implies 50(x+2y)=1800$

$\sf \implies x+2y = \dfrac{1800}{50}$

$\sf \implies x+2y = \dfrac{\cancel{1800}^{36}}{\cancel{50}}$

$\sf \implies x+2y = 36 \: \: - ②$

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On substraction of ① and ②,

(x+y) - (x+2y) = 24 - 36

x + y - x - 2y = - 12

- y = - 12

$\boxed{\sf y = 12}$ ⠀

Now, by putting y in ①,

x+y=24

x + 12 = 24

x = 24 - 12

$\boxed{\sf x=12}$

∴ Rs 50 notes, x = 12

and Rs 100 notes, y = 12