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The human eye has an approumate angular resolution of 5 x 10-4 rad and a typical photoprinter prints a minimum 500 dots per inch (1 inch = 2.54
cm) Af what minimum distance should a printed page be held so that one does not see individual dots?
o 10 16 cm
156 cm
20 16 cm
14 16 cm
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Answer:
murgi dim dite pare kintu kono manush ai prisner uttor dite parbena
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Explanation:
Given The human eye has an approximate angular resolution of 5 x 10-4 rad and a typical photo printer prints a minimum 500 dots per inch (1 inch = 2.54 cm) At what minimum distance should a printed page be held so that one does not see individual dots?
- So we have number of dots in 1 inch will be 500 dots
- So 1 inch = 2.54 cm
- So 2.54 cm has 500 dots.
- So distance between 2 dots will be 2.54 / 500
- = 0.00508 cm
- So if l represent distance between 2 dots and there is a human eye.
- So we need to find minimum distance so that eye does not see the dots. So the angle formed is theta.
- So we have theta = arc length l / r
- So r = l / theta or phi
- = 0.00508 / 0.0005
- So r = 10.16 cm
- So the minimum distance to hold the sheet will be 10.16 cm
Reference link will be
https://brainly.in/question/16920654
https://brainly.in/question/16154734
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