Physics, asked by adnan232, 5 months ago

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The human eye has an approumate angular resolution of 5 x 10-4 rad and a typical photoprinter prints a minimum 500 dots per inch (1 inch = 2.54
cm) Af what minimum distance should a printed page be held so that one does not see individual dots?
o 10 16 cm
156 cm
20 16 cm
14 16 cm​

Answers

Answered by mdmehedihasantanzid
0

Answer:

murgi dim dite pare kintu kono manush ai prisner uttor dite parbena

Answered by knjroopa
0

Explanation:

Given The human eye has an approximate angular resolution of 5 x 10-4 rad and a typical photo printer prints a minimum 500 dots per inch (1 inch = 2.54  cm) At what minimum distance should a printed page be held so that one does not see individual dots?  

  • So we have number of dots in 1 inch will be 500 dots
  • So 1 inch = 2.54 cm
  • So 2.54 cm has 500 dots.
  • So distance between 2 dots will be 2.54 / 500
  •                                                   = 0.00508 cm
  • So if l represent distance between 2 dots and there is a human eye.
  • So we need to find minimum distance so that eye does not see the dots. So the angle formed is theta.
  • So we have theta = arc length l / r
  •                        So r = l / theta or phi
  •                               = 0.00508 / 0.0005
  •                       So r = 10.16 cm
  • So the minimum distance to hold the sheet will be 10.16 cm

Reference link will be

https://brainly.in/question/16920654

https://brainly.in/question/16154734

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