Physics, asked by susisrinee, 11 months ago

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Question Type: MCQ
Question No. 28
Two liquids are allowed to flow through two capillary tubes of lengths in the ratio 1:2 and radii in the ratio 2.3
under the same pressure difference. If the volume rates of flow of the liquids are in the ratio 8:9, the ratio of
their coefficients of viscosity is
1.1 3 2.3.1 3.49 4.94
1​

Answers

Answered by DMani3
0

Answer:

The answer is option (3) 4:9 (or) 4/9

Attachments:
Answered by MrBhukkad
3

\huge{ \bigstar}\huge{\mathcal{ \overbrace{ \underbrace{ \pink{ \fbox{ \green{ \blue{S} \pink{o} \red{l} \green{u} \purple{t} \blue{i} \green{o} \red{n}}}}}}}} \huge{ \bigstar}

 \bf{From \: poiseullies \: eq^{n} \: } \sf{,Q=  \frac{\pi p {r}^{4} }{8ηL} </p><p>} \\   \bf{According \: to \: Question,} \\  \longrightarrow \bf{ \:  \frac{8}{9} =  \frac{ {2}^{4}  \times η_{2}}{ {3}^{4}  \times η_{1}} \times 2 } \\ \longrightarrow  \bf{ \frac{8}{9}  =  \frac{16 \times 2 \times η_2}{81 \timesη_1 } } \\  \longrightarrow \bf{ \frac{η_1}{η_2}  =  \frac{ \cancel{32} \times  \cancel9}{ \cancel{81} \times  \cancel8}  =  \frac{4}{9}} \\  \longrightarrow \bf{{η_1} : {η_2}  = 4 :9}

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