Chemistry, asked by thrishashashikumar, 9 months ago

Vihaan wanted to find the solubility of common salt in water. He prepared a saturated solution of common salt in water by dissolving salt and stirring it , repeating the process till the added salt remained undissolved. He than filtered the solution to separate the undissolved salt from the solution. The filtrate was the saturated solution of common salt in water. He took 10ml if this solution in a pre weighted China dish (w g) and found the mass of China dish +10mL of saturated solution (w1g) .He then evaporated the solution to dryness ( only salt was left behind in China dish ). After cooling he found the mass of China dish +salt (w2g). Use this data and arrive at a formula to find the solubility of common salt at room temperature.​

Answers

Answered by shiva0064
1

Answer:

salt in water. He prepared a saturated solution of common salt in water by dissolving salt and stirring it , repeating the process till the added salt remained undissolved. He than filtered the solution to separate the undissolved salt from the solution. The filtrate was the saturated solution of common salt in water. He took 10ml if this solution in a pre weighted China dish (w g) and found the mass of China dish +10mL of saturated solution (w1g) .He then evaporated the solution to dryness ( only salt was left behind in China dish ). After cooling he found the mass of China dish +salt (w2g). Use this data and arrive at a formula to find the solubility of common salt at room temperature.

Similar questions