Math, asked by shivamrai443468, 6 hours ago

(vii) 27x6 +64 (x + 1)3 factorise

Answers

Answered by yashasvinisinha
0

Answer:

Step by Step Solution

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

27*x^6-(64*x^3)=0

Step by step solution :

STEP

1

:

Equation at the end of step 1

(27 • (x6)) - 26x3 = 0

STEP

2

:

Equation at the end of step

2

:

33x6 - 26x3 = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

27x6 - 64x3 = x3 • (27x3 - 64)

Trying to factor as a Difference of Cubes:

4.2 Factoring: 27x3 - 64

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0-b3 =

a3-b3

Check : 27 is the cube of 3

Check : 64 is the cube of 4

Check : x3 is the cube of x1

Factorization is :

(3x - 4) • (9x2 + 12x + 16)

Trying to factor by splitting the middle term

4.3 Factoring 9x2 + 12x + 16

The first term is, 9x2 its coefficient is 9 .

The middle term is, +12x its coefficient is 12 .

The last term, "the constant", is +16

Step-1 : Multiply the coefficient of the first term by the constant 9 • 16 = 144

Step-2 : Find two factors of 144 whose sum equals the coefficient of the middle term, which is 12 .

-144 + -1 = -145

-72 + -2 = -74

-48 + -3 = -51

-36 + -4 = -40

-24 + -6 = -30

-18 + -8 = -26

For tidiness, printing of 24 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

4

:

x3 • (3x - 4) • (9x2 + 12x + 16) = 0

STEP

5

:

Theory - Roots of a product

5.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

5.2 Solve : x3 = 0

Solution is x3 = 0

Solving a Single Variable Equation:

5.3 Solve : 3x-4 = 0

Add 4 to both sides of the equation :

3x = 4

Divide both sides of the equation by 3:

x = 4/3 =

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