Question

vii.
A compound forms hcp structure.
Number of octahedral and tetrhedral
voids in 0.5 mole 6f substance is
respectively
a. 3.011*1023, 6.022x1023
b. 6.022x1023, 3.011*1023
c. 4.011x1023, 2.011x1023
d. 6.011x1023, 12.022x1023​

Answer 1

Answer:This may help you

Explanation:

Number of close-packed particles

= 0.5×6.022×1023= 3.011×1023

Therefore, number of octahedral voids = 3.011×1023

And, number of tetrahedral voids

= 2×3.011×1023= 6.022×1023

Therefore, total number of voids

= 3.011×1023+ 6.022×1023= 9.033×1023