Question

(vii) A girl is x years old. Her father is 5 more
than 2 times her age. The sum of their ages
is 50 years.
(viii) I think of a number, multiply it by 5 and then
subtract 9. The result is 11.​

Answer 1

Answer:

Acc. to Question

y = 5+ 2x

x+y = 50

== x = 50- y

put x= 50 - y in eq 1

y = 5+ 2(50 - y )

y= 5 + 100 - 2y

3y = 105

y = 35.

therefore x= 15

Answer 2

Answer:

(vii) - x = 15

(viii) - x = 4

Step-by-step explanation:

(vii)  girl = x

      father = 5 + 2x

      sum of their ages = 50

       so, x + 5 + 2x = 50

       3x + 5 = 50

        3x = 50 - 5

        3x = 45

        x = 45/3

        x = 15

(viii)  let the number be x

       5x - 9 = 11

       5x = 11 + 9

       5x = 20

       x = 20/5

       x = 4

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