Question

vii) A man is 4 times as old as his son. After 16 years, he will be only
twice as old as his son. Find their present ages.

Answer 1

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

4x+16 = 2(x+16)4x+16=2(x+16)

\implies 4x+16 = 2x+32⟹4x+16=2x+32

\implies 4x-2x=32-16⟹4x−2x=32−16

\implies 2x=16⟹2x=16

\implies x = \frac{16}{2}⟹x=

2

16

\implies x = 8 ⟹x=8

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

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