Question

vii) A mixture of methyl iodide and ethyl iodide in equal proportion is treated with sodium
dry ether then the number of products formed are ....
a) 1 b) 2 c) 3 d) 4.​

Answer 1

Answer:

2

Explanation:

This reaction is called as Wurtz Reaction

and it is used for the manufacture of even number of Carbons atom

not odd ones

thus

only Methyl iodide will react

forming NaI and Ethane

Answer 2

A mixture of methyl iodide and ethyl iodide in equal proportion is treated with sodium dry ether then the number of products formed is two.

Explanation: This reaction is an example of Wurtz's reaction

$C_2H_5I+2Na+CH_3I\rightarrow C_3H_8+2NaI$

In Wurtz's reaction, sodium metal reacts with two alkyl halides in the presence of a dry ether solution to create a higher alkane and a molecule that contains both sodium and the halogen. This is an example of an organic chemical coupling reaction.

For the synthesis of alkanes, the Wurtz reaction is a very helpful reaction in the domains of organic chemistry and organometallic chemistry. With the aid of sodium and dry ether solution, two distinct alkyl halides are coupled in this reaction to produce a longer alkane chain.

The French chemist Charles Adolphe Wurtz, who developed the aldol reaction as well, is honoured by the name of this reaction. In addition to sodium, the Wurtz reaction can also be used to produce alkanes from metals like silver, indium, activated copper, zinc, and iron.

Free radicals play a role in the reaction's process, opening the door to potential side reactions that result in the production of alkenes as the end result.

To learn more about Wurtz Reaction, click on the links below:

https://brainly.in/question/6335421?msp_srt_exp=5

https://brainly.in/question/49691030

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