Question

VII. A train is starting from a railway station and moving with uniform acceleration attains a speed 40
km/h in 10 minutes. Find its acceleration?
(2 mark)​

Answer 1

Answer:

a = $\frac{v-u}{t}$ [v=40 km/h > m/s = (40 x 1000)/ 1 x 60 x 60 = 11.1 m/s, t= 10 x 60= 600s]

  =  $\frac{11.1\\-0}{600}$

  =    0.0185 m/s^2

Explanation:

Here v stands for final velocity. Here u stands for initial velocity, as it starts from rest therefore initial velocity, u = 0.

1km = 1m therefore 40 x 1000 = 40000km

1 hr = 60 min, 1 min = 60s, therefore 1 hr x 60 min x 60s = 3600 s

km/h means $\frac{km}{h\\}$ so m/s means $\frac{m}{s}$  >>

m/s = $\frac{40000}{3600}$ = 11.1 m/s

[ 1 min = 60s] Therefore 10 min x 60s = 600s

a = $\frac{11.1 - 0}{600\\}$ = 0.0185 m/s^2