Question

vii) A TV tower has a height of 200 m.
How much population is covered by TV
transmission if the average population
density around the tower is 1000/km??
(Radius of the Earth = 6.4x10m)​

Answer 1

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Explanation:

Here, h=100m;

R=6.37×10

6

m;

Population density, ρ=1000km

−2

1000×10

−6

m

−6

m

−2

=10

−3

m

−2

Population covered = ρπd

2

=ρπ(2hR)

=10

−3

×

7

22

×2×100×6.37×10

6

40×10

5

=40lakhs

Now, d

′

=

2h

′

R

=2d=2

2hR

or h

′

=4h=4×100=400m

Increase in height of tower = h

′

−h

=400-100 = 300m.