(vii) cos
+ cos?
2 - cos 7 = 2 cost /. cos sin
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Answer:
Two numbers are such that the ratio between them is 3:5.If each is increased by 10 ,the ratio between the new numbers so formed is 5:7
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ToFind:−
Original number
\small\bold{\underline{\sf{\pink{Solution:-}}}}
Solution:−
Let the number be 3x and 5x
According to the given condition
Each number is increased by 10 ,the ratio between the new numbers so formed is 5:7
3x + 10/5x + 10 = 5/7
7(3x + 10) = 5(5x + 10)
21x + 70 = 25x + 50
21x - 25x = 50 - 70
- 4x = - 20
x = 20/4 = 5
Hence,
Required numbers
First number = 3x = 15
Second number = 5x = 25
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