Question

vii) Derive the formula for the range and
maximum height achieved by a projectile
thrown from the origin with initial
velocity u at an angel to the horizontal.​

Answer 1

Explanation:

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Answer 2

Answer:

Initial velocity = u

Angle of throw the horizontal= ∅

therefore vertical components of velocity=uSin∅

therefore At the max height, its velocity becomes one

therefore v²-u²=2gh

now, here final velocity is one , and it is going one opposite direction.

or

we can say gravity works opposite to the motion.

so,

∅²=(uSin∅)² = 2 x (-g) x h

h= u²Sin²∅

2g

solution = u²Sin²∅

2g

Explanation:

diagram in attachment ok

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