Question

.
(vii) if x = a sec0, y = b tan, then find the relation between x and
y free from theta​

Answer 1

Answer:

x²/a²-y²/b²=1

Step-by-step explanation:

x = a secθ (given)

x/a=secθ -(i)

y = b tanθ(given)

y/b=tanθ-(ii)

Squaring and subtracting (i) from (ii)

x²/a²-y²/b²=sec²θ-tan²θ

(sec²θ-tan²θ=1)

x²/a²-y²/b²=1