Question

VII. Solve the following problems : 1. If mass a planet is four times the mass of the earth and its radius is twice the radius of the earth. What will be the escape velocity for that planet?​

Answer 1

Answer:

5m/$s^{2}$

Explanation:

q  ′  =  2 GM/$R^{2}$

    ​ =  G×2me/$(4ve)^{2}$

    ​ =   1/8   Gme/$ve^{2}$

    =   g/8

​ To find 4 times the acceleration due to gravity

=4× g/8=g/2

​=  10/2

​=5m/$s^{2}$

Hence, the answer is 5m/$s^{2}$

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