Question

(vii) The factors of a2 – 2a -48 are (a) (a - 6) (a + 8) (b) (a - 3) (a + 16) (c) (a + 6) (a - 8) (d) (a + 4) (a – 12)

Answer 1

Answer:

answer is given above hope this answer will help you answer is option (c)

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Answer 2

★ Answer :

→ a² - 2a - 48 = 0 we have to find the factors of the polynomial.

→ a² - 8a + 6a - 48 = 0

→ a(a - 8) +6(a - 8) = 0

→ (a + 6) (a - 8) = 0

→ a + 6 = 0

→ a = -6

Or

→ a - 8 = 0

→ a = 8

so, Option C is correct.

$\rule{200}{1}$

For factorising we have to follow these given below steps :

Let polynomial be ax² + bx + c = 0

• Firstly we will multiply a and c.
• Then we will make the factors of their product.
• The factors must be equal to b on adding or subtracting.
• Then, we will take common.