Question

(vii) x to the power 5 cosec x differentiate it ...​

Answer 1

Answer:

x^4 cosec x( -x cot x+5x)

Step-by-step explanation:

x^5 cosec x=?

we know that

d(uv)=udv+vdu ...(1)

here u=x^5 and y=cosec x

du= 5x^4

dv=-cosec x cot x

now (1) becomes

d(x^5 cosec x)=x^5(-cosec x cot x )+cosec x(5x^4)

on taking x^4 cosec x as common,

d( x^5 cosec x)=x^4 cosec x(-x cot x+ 5 x)

this is the answer. hope it helps.