(vii) y = x^n(1 - x)^n
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Answer:
Given,
x
n
+y
n
x
n+1
+y
n+1
=
xy
.......... Geometric mean
⇒x
n+1
+y
n+1
=
xy
(x
n
+y
n
)
⇒x⋅x
n
−x
n
⋅x
2
1
⋅y
2
1
=y
n
⋅x
2
1
⋅y
2
1
−y⋅y
n
⇒x
n+
2
1
(
x
2
1
−y
2
1
)=y
n+
2
1
(
x
2
1
−y
2
1
)
⇒(
y
x
)
n+
2
1
=1
⇒(
y
x
)
n+
2
1
=(
y
x
)
0
⇒n+
2
1
=0⇒n=−
2
1
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