Question

(viii) 25x2 30x+7=0 by sridhara
acharaya formula ​

Answer 1

Case;-1

We Have

⇒25x² + 30x +7x = 0

Now compare with

⇒ax² + bx + c = 0

Where

⇒a = 25 , b = 30 and c = 7

Sridharacharya formula

⇒x = (-b±√D)/2a

Where D is Discriminant

⇒D= b² - 4ac

Now find D

⇒D = (30)² - 4×25×7

⇒D = 900 - 700

⇒D = 200

Now

⇒x = (-b±√D)/2a

⇒x = (-30±√(200))/2(25)

⇒x = (-30±10√2)/100

⇒x = 10(-3+√2)/100     and   x = 10(-3-√2)/100

⇒x = (-3+√2)/10     and x = (-3-√2)/10

Case;-2

We Have

⇒25x² - 30x +7x = 0

Now compare with

⇒ax² + bx + c = 0

Where

⇒a = 25 , b = -30 and c = 7

Sridharacharya formula

⇒x = (-b±√D)/2a

Where D is Discriminant

⇒D= b² - 4ac

Now find D

⇒D = (-30)² - 4×25×7

⇒D = 900 - 700

⇒D = 200

Now  

⇒x = (-b±√D)/2a

⇒x = (-(-30)±√(200))/2(25)

⇒x = (30±10√2)/100

⇒x = 10(3+√2)/100     and   x = 10(3-√2)/100

⇒x = (3+√2)/10     and x = (3-√2)/10

Answer 2

Correct Question:

• 25x² + 30x +7x = 0 or,
• 25x² - 30x +7x = 0

Solution:

• 25x² + 30x +7x = 0

Quadratic equation :

➡ax² + bx + c = 0

Where

➡a = 25 , b = 30 and c = 7

Sridharacharya formula

➡x = (-b±√D)/2a

Where D is Discriminant

➡D= b² - 4ac

So,

➡D = (30)² - 4×25×7

➡D = 900 - 700

➡D = 200

Now

➡x = (-b±√D)/2a

➡x = (-30±√(200))/2(25)

➡x = (-30±10√2)/100

➡x = 10(-3+√2)/100 or x = 10(-3-√2)/100

•°• x = (-3+√2)/10 or x = (-3-√2)/10

________________________________

• 25x² - 30x +7x = 0

Quadratic equation:

➡ax² + bx + c = 0

Where

➡a = 25 , b = -30 and c = 7

Sridharacharya formula

➡x = (-b±√D)/2a

Where D is Discriminant

➡D= b² - 4ac

So,

➡D = (-30)² - 4×25×7

➡D = 900 - 700

➡D = 200

Now

➡x = (-b±√D)/2a

➡x = (-(-30)±√(200))/2(25)

➡x = (30±10√2)/100

➡x = 10(3+√2)/100 or x = 10(3-√2)/100

➡x = (3+√2)/10 or x = (3-√2)/10