Question

(viii) 3p?q? - 4pq + 5,- 10 p?q?, 15 + 9pq + 7p?q?
(ix) ab – 4a, 4b - ab, 4a – 4b
(x) x2 - y2 – 1, y2 - 1 - x2, 1 - x2 - y2​

Answer 1

Answer and Step-by-step Explanation:

$Add.$

3p²q² - 4pq + 5, -10p²q², 15 + 9pq + 7p²q²

= 3p²q² - 4pq + 5, -10p²q², 15 + 9pq + 7p²q²

= 3p²q² - 4pq + 5 + (-10p²q²) + 15 + 9pq + 7p²q²

= 3p²q² - 10p²q² + 7p²q² + 4pq + 9pq + 5 + 15

= (3 - 10 + 7) p²q² + (-4 + 9) pq + 20

= 0 p²q² + 5pq +20

= 5pq + 20

$Answer:$ 5pq + 20

ab − 4a, 4b − ab, 4a − 4b

= ab − 4a, 4b − ab,4a − ab

= ab − 4a + 4b − ab + 4a − ab

= −4a + 4a + 4b − 4b + ab − ab

= 0

$Answer:$ 0

x² - y² - 1, y² - 1 - x², 1 - x² - y²

= x² - y² - 1, y² - 1 - x², 1 - x² - y²

= x² - y² - 1 + y² - 1 - x² + 1 - x² - y²

= x² - x² - x² - y² + y² - y² - 1 - 1 + 1

= (1 − 1 − 1) x² + (−1 + 1 − 1) y² - 1 - 1 + 1  

= x² - y² - 1

$Answer:$ x² - y² - 1