Question

viii. A cyclist is traveling at 7m s -1, then accelerates at 2.5m s -2 for 15 seconds.
a. How far did they travel during this time?
b. What was the final speed after 15 seconds

Answer 1

Answer:

47.5m, 67m/s

Explanation:

here initial velocity (u)= 7m/s

Acceleration (a) = 2.5ms -2

time=5 sec

how far they travelled is distance = ut+1/2 at^2

= 7m/s x 5s + 2.5m/s^-2 x (5s)^2

= 35m + 12.5m

= 47.5m

the object travelled 47.5m

final velocity= u+at

= 7m/s + 2.5ms-2 x 5second

= 7m/s + 12.5m/s x 5

= (7+60) m/s

= 67m/s

final velocity=67m/s after 15 seconds of travelling.

Hope you liked the solution please mark me a the brainliest