Question

(viii) A signal of Maximum Frequency = 20KHz is sampled at nyquist rate. The time interval
between two successive samples is (a) 251s (b) 2.5us (c)50us (d) 20ms.​

Answer 1

50 us

Explanation:

f=1/T

f=1/20000 1kHz =1000Hz

f=50us

Answer 2

Given:

Signal with a maximum frequency = 20KHz = 20 X 10³ Hz

To Find:

The time interval  between two successive samples

Solution:

The time interval  between two successive samples is equal to the time period of the signal.

We know that frequency is the reciprocal of the time period

So, the time period of the given signal = 1/f

= 1/20 X 10³ Hz

= 0.05 X 10⁻³ s

= 50 X 10 ⁻⁶

= 50μs

Hence, the time interval  between two successive samples is 50μs.