Question

(viii) Capacity of a parallel capacitor with dielectric constant 5
is 40 uF. Calculate the capacity of the same capacitor when
dielectric material is removed.​

Answer 1

Answer:

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Answer 2

Answer:

When a dielectric constant is present, capacitance is given by

C' = C × k

C' = 40 uF ( Since dielectric is present)

When dielectric is removed, capacitance reduces by a factor of k

C = C' / k

= 40uF / 5

= 8 uF

Explanation:

When dielectric is removed general trick is to divide the capacitance by dielectric constant :)