Question

viii) If the frequency of revolution of a proton (q = 1.6 x 10-19 coulomb) in a uniform magnetic induction is 10 Hz, what is the corresponding electric current ?​

Answer 1

Answer:

sorry answers pati nhi hai

Answer 2

Given : B=3.5Wb/m

2

m=1.67×10

−27

kg, q=1.6×10

−19

C,

t=?

t=

2

T

=

qB

πm

=

1.6×10

−19

×3.5

3.14×1.67×10

−27

=9.36×10

−9

sec.