Question

(viii) If x = 1, y = -2 and z = 3,
find the value of x² + y² + z² – 2xyz.​

Answer 1

Step-by-step explanation:

1^2 +(-2^2)+3^3

1^2 +(-2^2)+3^31-4+9

1^2 +(-2^2)+3^31-4+910-4

1^2 +(-2^2)+3^31-4+910-46 is the answer

Answer 2

Answer:

(X)² + (y)² + (Z)² - 2 xyz

= (1)² + (-2)² + (3)² - 2 x 1 x (-2) x 3

= 1 + 4 + 9 - 12

= 5+9-12

= 14 - 12

= 2