Question

(viii) In hydrogen atom, electron jumps from the 3 orbit to the
1St orbit. The change in angular momentum is
va) 1-05 x 10-34Js (b) 2-11x10 3+JS
(c) 3.16x10-3+1 (d) 4.22x10-34 Us​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

In hydrogen atom, electron jumps from the 3 orbit to the 1st orbit. The change in angular momentum is

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Electron jumps from ${\sf 3^{rd}\: orbit\:to\:1^{st}\:orbit}$
• ⛬ ${\sf n_2=3\:\:and\:\:n_1=1}$

$\large\underline{\underline{\sf To\:Find:}}$

• Change in Angular Momentum ${\sf \triangle L}$

✪$\large{\boxed{\bf \blue{\triangle L=mvr=\dfrac{nh}{2π}} }}$

$\implies{\sf \triangle L = L_2-L_1 }$

$\implies{\sf \triangle L = \dfrac{n_2h}{2π}-\dfrac{n_1h}{2π} }$

$\implies{\sf \dfrac{3h}{2π}-\dfrac{h}{2π} }$

$\implies{\sf \dfrac{3h-h}{2π}}$

$\implies{\sf \dfrac{2h}{2π}}$

$\implies{\sf \dfrac{h}{π}}$

$\implies{\sf \dfrac{6.6×10^{-34}}{3.14}}$

$\implies{\sf 2.1×10^{-34}}$

$\implies{\bf \red{\triangle L=2.1×10^{-34}\:Js} }$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Change in Angular Momentum is ${\bf \red{ 2.1×10^{-34}Js}}$.

Answer 2

In hydrogen atom, electron jumps from the 3 orbit to the 1st orbit. The change in angular momentum is

\huge\underline{\underline{\bf \orange{Solution-}}}

Solution−

\large\underline{\underline{\sf Given:}}

Given:

Electron jumps from {\sf 3^{rd}\: orbit\:to\:1^{st}\:orbit}3

rd

orbitto1

st

orbit

⛬ {\sf n_2=3\:\:and\:\:n_1=1}n

2

=3andn

1

=1

\large\underline{\underline{\sf To\:Find:}}

ToFind:

Change in Angular Momentum {\sf \triangle L}△L

✪\large{\boxed{\bf \blue{\triangle L=mvr=\dfrac{nh}{2π}} }}

△L=mvr=

2π

nh

\implies{\sf \triangle L = L_2-L_1 }⟹△L=L

2

−L

1

\implies{\sf \triangle L = \dfrac{n_2h}{2π}-\dfrac{n_1h}{2π} }⟹△L=

2π

n

2

h

−

2π

n

1

h

\implies{\sf \dfrac{3h}{2π}-\dfrac{h}{2π} }⟹

2π

3h

−

2π

h

\implies{\sf \dfrac{3h-h}{2π}}⟹

2π

3h−h

\implies{\sf \dfrac{2h}{2π}}⟹

2π

2h

\implies{\sf \dfrac{h}{π}}⟹

π

h

\implies{\sf \dfrac{6.6×10^{-34}}{3.14}}⟹

3.14

6.6×10

−34

\implies{\sf 2.1×10^{-34}}⟹2.1×10

−34

\implies{\bf \red{\triangle L=2.1×10^{-34}\:Js} }⟹△L=2.1×10

−34

Js

\huge\underline{\underline{\bf \orange{Answer-}}}

Answer−

Change in Angular Momentum is {\bf \red{ 2.1×10^{-34}Js}}2.1×10

−34

Js .